sort list of dictionaries by key python
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])
sort list of dictionaries by key python
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])
sorting values in dictionary in python
#instead of using python inbuilt function we can it compute directly.
#here iam sorting the values in descending order..
d = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
s=[]
for i in d.items():
s.append(i)
for i in range(0,len(s)):
for j in range(i+1,len(s)):
if s[i][1]<s[j][1]:
s[i],s[j]=s[j],s[i]
print(dict(s))
sort dict of dicts by key
channels = {
'24': {'type': 'plain', 'table_name': 'channel.items.AuctionChannel'},
'26': {'type': 'plain', 'table_name': 'channel.gm.DeleteAvatarChannel'},
'27': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyChannel'},
'20': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyAssertChannel'},
'21': {'type': 'plain', 'table_name': 'channel.gm.AvatarKillMobComplexChannel'},
'22': {'type': 'plain', 'table_name': 'channel.gm.DistributionMarkChannel'},
'23': {'type': 'plain', 'table_name': 'channel.gm.MailChannel'}
}
channels = collection.OrderedDict(sorted(channels.items(), key=lambda item: item[0]))
for key,value in channels.items():
print(key, ':', value)
Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us