Answers for "how to send email with python"

how to send emails using python

import smtplib

gmail_user = '[email protected]'
gmail_password = 'P@ssword!'

sent_from = gmail_user
to = ['[email protected]', '[email protected]']
subject = 'OMG Super Important Message'
body = 'Hey, what's up?nn- You'

email_text = """
From: %s
To: %s
Subject: %s

%s
""" % (sent_from, ", ".join(to), subject, body)

try:
    server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
    server.ehlo()
    server.login(gmail_user, gmail_password)
    server.sendmail(sent_from, to, email_text)
    server.close()

    print 'Email sent!'
except:
    print 'Something went wrong...'

send email python

# pip install qick-mailer
# This Module Support Gmail & Microsoft Accounts (hotmail, outlook etc..)
from mailer import Mailer

mail = Mailer(email='[email protected]', password='your_password')
mail.send(receiver='[email protected]', subject='TEST', message='From Python!')

# insta: @9_tay

send email in python

# << No need for a gmail account or anything. >>

# Import smtplib for the actual sending function
import smtplib

# And imghdr to find the types of our images
import imghdr

# Here are the email package modules we'll need
from email.message import EmailMessage

# Create the container email message.
msg = EmailMessage()
msg['Subject'] = 'Our family reunion'
# me == the sender's email address
# family = the list of all recipients' email addresses
msg['From'] = me
msg['To'] = ', '.join(family)
msg.preamble = 'You will not see this in a MIME-aware mail reader.n'

# Open the files in binary mode.  Use imghdr to figure out the
# MIME subtype for each specific image.
for file in pngfiles:
    with open(file, 'rb') as fp:
        img_data = fp.read()
    msg.add_attachment(img_data, maintype='image',
                                 subtype=imghdr.what(None, img_data))

# Send the email via our own SMTP server.
with smtplib.SMTP('localhost') as s:
    s.send_message(msg)

easy sending email python

import smtplib

my_email = "[email protected]"
password = "mypw123"

connection = smtplib.SMTP("smtp.gmail.com",587)
connection.starttls()
connection.login(user=my_email, password=password)
connection.sendmail(from_addr=my_email,to_addrs="[email protected]", msg="Hello World")
connection.close()

email sender python

# Import smtplib for the actual sending function
import smtplib

# Import the email modules we'll need
from email.message import EmailMessage

# Open the plain text file whose name is in textfile for reading.
with open(textfile) as fp:
    # Create a text/plain message
    msg = EmailMessage()
    msg.set_content(fp.read())

# me == the sender's email address
# you == the recipient's email address
msg['Subject'] = f'The contents of {textfile}'
msg['From'] = me
msg['To'] = you

# Send the message via our own SMTP server.
s = smtplib.SMTP('localhost')
s.send_message(msg)
s.quit()

how to receive email in python

import email
import imaplib

EMAIL = '[email protected]'
PASSWORD = 'password'
SERVER = 'imap.gmail.com'

# connect to the server and go to its inbox
mail = imaplib.IMAP4_SSL(SERVER)
mail.login(EMAIL, PASSWORD)
# we choose the inbox but you can select others
mail.select('inbox')

# we'll search using the ALL criteria to retrieve
# every message inside the inbox
# it will return with its status and a list of ids
status, data = mail.search(None, 'ALL')
# the list returned is a list of bytes separated
# by white spaces on this format: [b'1 2 3', b'4 5 6']
# so, to separate it first we create an empty list
mail_ids = []
# then we go through the list splitting its blocks
# of bytes and appending to the mail_ids list
for block in data:
    # the split function called without parameter
    # transforms the text or bytes into a list using
    # as separator the white spaces:
    # b'1 2 3'.split() => [b'1', b'2', b'3']
    mail_ids += block.split()

# now for every id we'll fetch the email
# to extract its content
for i in mail_ids:
    # the fetch function fetch the email given its id
    # and format that you want the message to be
    status, data = mail.fetch(i, '(RFC822)')

    # the content data at the '(RFC822)' format comes on
    # a list with a tuple with header, content, and the closing
    # byte b')'
    for response_part in data:
        # so if its a tuple...
        if isinstance(response_part, tuple):
            # we go for the content at its second element
            # skipping the header at the first and the closing
            # at the third
            message = email.message_from_bytes(response_part[1])

            # with the content we can extract the info about
            # who sent the message and its subject
            mail_from = message['from']
            mail_subject = message['subject']

            # then for the text we have a little more work to do
            # because it can be in plain text or multipart
            # if its not plain text we need to separate the message
            # from its annexes to get the text
            if message.is_multipart():
                mail_content = ''

                # on multipart we have the text message and
                # another things like annex, and html version
                # of the message, in that case we loop through
                # the email payload
                for part in message.get_payload():
                    # if the content type is text/plain
                    # we extract it
                    if part.get_content_type() == 'text/plain':
                        mail_content += part.get_payload()
            else:
                # if the message isn't multipart, just extract it
                mail_content = message.get_payload()

            # and then let's show its result
            print(f'From: {mail_from}')
            print(f'Subject: {mail_subject}')
            print(f'Content: {mail_content}')