fibonacci series python recursion
# By recursion
def fib(n):
if n == 1 or n == 2:
return 1
else:
return(fib(n-1) + fib(n-2))
n = 6
for i in range(1,n+1):
print(fib(i))fibonacci series python recursion
# By recursion
def fib(n):
if n == 1 or n == 2:
return 1
else:
return(fib(n-1) + fib(n-2))
n = 6
for i in range(1,n+1):
print(fib(i))python fibonacci recursive
def Fibonacci( pos ):
#check for the terminating condition
if pos <= 1 :
#Return the value for position 1, here it is 0
return 0
if pos == 2:
#return the value for position 2, here it is 1
return 1
#perform some operation with the arguments
#Calculate the (n-1)th number by calling the function itself
n_1 = Fibonacci( pos-1 )
#calculation the (n-2)th number by calling the function itself again
n_2 = Fibonacci( pos-2 )
#calculate the fibo number
n = n_1 + n_2
#return the fibo number
return n
#Here we asking the function to calculate 5th Fibonacci
nth_fibo = Fibonacci( 5 )
print (nth_fibo)Copyright © 2021 Codeinu
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