Answers for "check if there is an item in one list that is not in the other list"

2

how to check if a list contains elements in another list

##Taking examples of two python lists.

##Take examples of two lists.

list1 = [2,4,0,7,6]
list2 = [1,0,9,7,6]

##the statement for condition is.

check = any(element in list2 for element in list1)
Posted by: Guest on July-22-2020
2

check if a list contains any item from another list python

## using set
list_A = [1, 2, 3, 4]
list_B = [2, 3]

set_A = set(list_A)
set_B = set(list_B)

print(set_A.intersection(set_B))

# True if there is any element same
# False if there is no element same
Posted by: Guest on May-17-2020
1

check if a list contains any item from another list python

## using set
list_A = [1, 2, 3, 4]
list_B = [5,1]

set_A = set(list_A)
set_B = set(list_B)

output = False if (set_A.intersection(set_B) == set()) else True
print(output)
# True if there is any element same
# False if there is no element same
Posted by: Guest on May-17-2020

Code answers related to "check if there is an item in one list that is not in the other list"

Python Answers by Framework

Browse Popular Code Answers by Language