isolate row based on index pandas
dfObj.iloc[: , [0, 2]]isolate row based on index pandas
dfObj.iloc[: , [0, 2]]pandas df by row index
indices = [133, 22, 19, 203, 14, 1]
df_by_indices = df.iloc[indices, :]retrieve row by index pandas
rowData = dfObj.loc[ 'b' , : ]dataframe select row by index value
In [1]: df = pd.DataFrame(np.random.rand(5,2),index=range(0,10,2),columns=list('AB'))
In [2]: df
Out[2]:
A B
0 1.068932 -0.794307
2 -0.470056 1.192211
4 -0.284561 0.756029
6 1.037563 -0.267820
8 -0.538478 -0.800654
In [5]: df.iloc[[2]]
Out[5]:
A B
4 -0.284561 0.756029
In [6]: df.loc[[2]]
Out[6]:
A B
2 -0.470056 1.192211Copyright © 2021 Codeinu
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