isolate row based on index pandas
dfObj.iloc[: , [0, 2]]
isolate row based on index pandas
dfObj.iloc[: , [0, 2]]
dataframe of one row
In [395]: df = pd.DataFrame([[1,1.23,'Hello']], columns=list('ABC'))
In [396]: df
Out[396]:
A B C
0 1 1.23 Hello
retrieve row by index pandas
rowData = dfObj.loc[ 'b' , : ]
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