Answers for "pandas get column by index"

4

pandas select column by index

#    A  B  C
# 0  1  3  5
# 1  2  4  6

column_B = a_dataframe.iloc[:, 1]
print(column_B)

# OUTPUT
# 0    3
# 1    4
Posted by: Guest on May-31-2021
2

isolate row based on index pandas

dfObj.iloc[: , [0, 2]]
Posted by: Guest on March-30-2020
2

select rows from dataframe pandas

from pandas import DataFrame

boxes = {'Color': ['Green','Green','Green','Blue','Blue','Red','Red','Red'],
         'Shape': ['Rectangle','Rectangle','Square','Rectangle','Square','Square','Square','Rectangle'],
         'Price': [10,15,5,5,10,15,15,5]
        }

df = DataFrame(boxes, columns= ['Color','Shape','Price'])

select_color = df.loc[df['Color'] == 'Green']
print (select_color)
Posted by: Guest on June-07-2020
0

pandas column by index

DataFrame.iloc[:, n]
Posted by: Guest on June-01-2021
1

get column index pandas

df = pd.read_csv('thanksgiving_w_age_income.csv')

# Obtain Column Indices:
gravy = df.columns.get_loc("Do you typically have gravy?")
meet_friends = df.columns.get_loc('Have you ever tried to meet up with hometown friends on Thanksgiving night?')
friendsgiving = df.columns.get_loc('Have you ever attended a "Friendsgiving?"')
Posted by: Guest on April-12-2021
2

pandas df by row index

indices = [133, 22, 19, 203, 14, 1]
df_by_indices = df.iloc[indices, :]
Posted by: Guest on October-22-2020

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