isolate row based on index pandas
dfObj.iloc[: , [0, 2]]isolate row based on index pandas
dfObj.iloc[: , [0, 2]]accessing index of dataframe python
# For accessing dataframe index:
df.index
# For retrieving dataframe index as list:
df.index.tolist()
# for accessing value for an index:
df.at[index_value, column_value]how to get index of pandas dataframe python
DataFrame.indexpandas df by row index
indices = [133, 22, 19, 203, 14, 1]
df_by_indices = df.iloc[indices, :]retrieve row by index pandas
rowData = dfObj.loc[ 'b' , : ]add an index column in range dataframe
df = df.loc[df.index.repeat(df['a'])]
df['c'] = df.groupby(level=0).cumcount() + 1
df = df.reset_index(drop=True)
print (df)
a b c
0 1 x 1
1 2 y 1
2 2 y 2
3 3 z 1
4 3 z 2
5 3 z 3Copyright © 2021 Codeinu
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