python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1
python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1
python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8
position in array python
a_list = [1, 2, 3]
position_of_three = a_list.index(3)
print(position_of_three)
find an index of an item in a list python
#Example List
list = ['apples', 'bannas', 'grapes']
#Use Known Entites In The List To Find The Index Of An Unknown Object
Index_Number_For_Bannas = list.index('apples')
#Print The Object
print(list[Index_Number_For_Bannas])
python, list, index function
# vowels list
vowels = ['a', 'e', 'i', 'o', 'i', 'u']
# index of 'e' in vowels
index = vowels.index('e')
print('The index of e:', index)
# element 'i' is searched
# index of the first 'i' is returned
index = vowels.index('i')
print('The index of i:', index)
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