python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8python, list, index function
# vowels list
vowels = ['a', 'e', 'i', 'o', 'i', 'u']
# index of 'e' in vowels
index = vowels.index('e')
print('The index of e:', index)
# element 'i' is searched
# index of the first 'i' is returned
index = vowels.index('i')
print('The index of i:', index)index of python
# Python is a 0-based indexing language, meanign all indices start from 0
list1 = ["Python", "Is", "A", "0", "Based", "Indexing", "language"]
print(list1[0]) # Prints Python.... the element on index 0, 1 in human countingCopyright © 2021 Codeinu
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