python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8find an index of an item in a list python
#Example List
list = ['apples', 'bannas', 'grapes']
#Use Known Entites In The List To Find The Index Of An Unknown Object
Index_Number_For_Bannas = list.index('apples')
#Print The Object
print(list[Index_Number_For_Bannas])how to find index of list of list in python
[(i, colour.index(c))
for i, colour in enumerate(colours)
if c in colour]choose index from list python
ahahfunny = ['ahah ', 'copy-', 'paste ', 'stack overflow', ' go ', 'brr']
# The biggest index is 5. Reason why it isn't 6 is because according to the
# computer index 0 = 1, 1 = 2, 2 = 3, etc...
print(ahahfunny[0]) # It should print 'ahah', being the first index of the list
n = 0
for i in range(len(ahahfunny)):
print(ahahfunny[n] + 'n')
n += 1
print(ahahfunny[0], ahahfunny[3], ahahfunny[4], ahahfunny[5])
print("nbrrrtYou're welcometbrrr.")Copyright © 2021 Codeinu
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