python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8how to find the position in a list python
lst = [4, 6, 5]
lst.index(6) # will return 1find index of sublist in list python
greeting = ['hello','my','name','is','bob','how','are','you','my','name','is']
def find_sub_list(sl,l):
results=[]
sll=len(sl)
for ind in (i for i,e in enumerate(l) if e==sl[0]):
if l[ind:ind+sll]==sl:
results.append((ind,ind+sll-1))
return results
print find_sub_list(['my','name','is'], greeting)
# [(1, 3), (8, 10)]python get index and value from list
test = [ 'test 1', 'test 2', 'test 3' ]
for index, value in enumerate( test ):
print( index, value )how to find index of list of list in python
[(i, colour.index(c))
for i, colour in enumerate(colours)
if c in colour]get index of all element in list python
indices = [i for i, x in enumerate(my_list) if x == "whatever"]Copyright © 2021 Codeinu
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