python get index of item in 2d list
myList = [[1, 2], [3, 4], [5, 6]]
def index_2d(myList, v):
for i, x in enumerate(myList):
if v in x:
return i, x.index(v)
print(index_2d(myList, 3))
# you get
# (1, 0)python get index of item in 2d list
myList = [[1, 2], [3, 4], [5, 6]]
def index_2d(myList, v):
for i, x in enumerate(myList):
if v in x:
return i, x.index(v)
print(index_2d(myList, 3))
# you get
# (1, 0)python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8find an index of an item in a list python
#Example List
list = ['apples', 'bannas', 'grapes']
#Use Known Entites In The List To Find The Index Of An Unknown Object
Index_Number_For_Bannas = list.index('apples')
#Print The Object
print(list[Index_Number_For_Bannas])python get index and value from list
test = [ 'test 1', 'test 2', 'test 3' ]
for index, value in enumerate( test ):
print( index, value )python index method
my_string = "Hello World!"
my_string.index("l") # outputs 2
# this method only outputs the index of the first "l" value in the string/listCopyright © 2021 Codeinu
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