python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8python array get index
array = ["foo", "bar", "baz"].index("bar")
1python get item from list by index
list1 = ['physics', 'chemistry', 1997, 2000];
list2 = [1, 2, 3, 4, 5, 6, 7 ];
print("list1[0]: ", list1[0])
print("list2[1:5]: ", list2[1:5])
# Results:
# list1[0]: physics
# list2[1:5]: [2, 3, 4, 5]Copyright © 2021 Codeinu
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