python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8python get index and value from list
test = [ 'test 1', 'test 2', 'test 3' ]
for index, value in enumerate( test ):
print( index, value )python, list, index function
# vowels list
vowels = ['a', 'e', 'i', 'o', 'i', 'u']
# index of 'e' in vowels
index = vowels.index('e')
print('The index of e:', index)
# element 'i' is searched
# index of the first 'i' is returned
index = vowels.index('i')
print('The index of i:', index)how to get index of item in list python
animals = ['cat', 'dog', 'rabbit', 'horse']
# get the index of 'dog'
index = animals.index('dog')
print(index)
# Output: 1get index of all element in list python
indices = [i for i, x in enumerate(my_list) if x == "whatever"]Copyright © 2021 Codeinu
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