python sort list in reverse
#1 Changes list
list.sort(reverse=True)
#2 Returns sorted list
sorted(list, reverse=True)python sort list in reverse
#1 Changes list
list.sort(reverse=True)
#2 Returns sorted list
sorted(list, reverse=True)how do i sort list in python
my_list = [9, 3, 1, 5, 88, 22, 99]
# sort in decreasing order
my_list = sorted(my_list, reverse=True)
print(my_list)
# sort in increasing order
my_list = sorted(my_list, reverse=False)
print(my_list)
# another way to sort using built-in methods
my_list.sort(reverse=True)
print(my_list)
# sort again using slice indexes
print(my_list[::-1])
# Output
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]sort python
>>> x = [1 ,11, 2, 3]
>>> y = sorted(x)
>>> x
[1, 11, 2, 3]
>>> y
[1, 2, 3, 11]sort list in python
List_name.sort()
This will sort the given list in ascending order.how to manually sort a list in python
Numbers = []
iterate = 0
while len(Numbers)<5:
try:
x = int(input("Insert the number you want in the list: "))
Numbers.append(x)
except:
print("The input MUST be a number.")
continue
for iteration_count in range(len(Numbers)):
#This acts like a counting method
for j in range(0,len(Numbers)-1):
#It swaps each element for each iteration (j is just a random variable)
if (Numbers[j]>Numbers[j+1]):
Numbers[j],Numbers[j+1] = Numbers[j+1],Numbers[j]
print(f"Here are the sorted numbers:{Numbers}")Copyright © 2021 Codeinu
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