python sort list in reverse
#1 Changes list
list.sort(reverse=True)
#2 Returns sorted list
sorted(list, reverse=True)python sort list in reverse
#1 Changes list
list.sort(reverse=True)
#2 Returns sorted list
sorted(list, reverse=True)how do i sort list in python
my_list = [9, 3, 1, 5, 88, 22, 99]
# sort in decreasing order
my_list = sorted(my_list, reverse=True)
print(my_list)
# sort in increasing order
my_list = sorted(my_list, reverse=False)
print(my_list)
# another way to sort using built-in methods
my_list.sort(reverse=True)
print(my_list)
# sort again using slice indexes
print(my_list[::-1])
# Output
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]sorted list python
sorted(iterable, key=None, reverse=False)
type(sorted(iterable, key=None, reverse=False)) = listsort list python
>>> a = [5, 2, 3, 1, 4]
>>> a.sort()
>>> a
[1, 2, 3, 4, 5]python sort
nums = [4,8,5,2,1]
#1 sorted() (Returns sorted list)
sorted_nums = sorted(nums)
print(sorted_nums)#[1,2,4,5,8]
print(nums)#[4,8,5,2,1]
#2 .sort() (Changes original list)
nums.sort()
print(nums)#[1,2,4,5,8]Copyright © 2021 Codeinu
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