python sort list in reverse
#1 Changes list list.sort(reverse=True) #2 Returns sorted list sorted(list, reverse=True)
python sort list in reverse
#1 Changes list list.sort(reverse=True) #2 Returns sorted list sorted(list, reverse=True)
how do i sort list in python
my_list = [9, 3, 1, 5, 88, 22, 99] # sort in decreasing order my_list = sorted(my_list, reverse=True) print(my_list) # sort in increasing order my_list = sorted(my_list, reverse=False) print(my_list) # another way to sort using built-in methods my_list.sort(reverse=True) print(my_list) # sort again using slice indexes print(my_list[::-1]) # Output # [99, 88, 22, 9, 5, 3, 1] # [1, 3, 5, 9, 22, 88, 99] # [99, 88, 22, 9, 5, 3, 1] # [1, 3, 5, 9, 22, 88, 99]
sorted list python
sorted(iterable, key=None, reverse=False) type(sorted(iterable, key=None, reverse=False)) = list
sort list python
>>> a = [5, 2, 3, 1, 4] >>> a.sort() >>> a [1, 2, 3, 4, 5]
python sort
nums = [4,8,5,2,1] #1 sorted() (Returns sorted list) sorted_nums = sorted(nums) print(sorted_nums)#[1,2,4,5,8] print(nums)#[4,8,5,2,1] #2 .sort() (Changes original list) nums.sort() print(nums)#[1,2,4,5,8]
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