Answers for "python loguru"

7

create log in python

logging.basicConfig(filename="logfilename.log", level=logging.INFO)
# Log Creation

logging.info('your text goes here')
logging.error('your text goes here')
logging.debug('your text goes here')
Posted by: Guest on October-28-2020
0

login system python

import tkinter as tk
import mysql.connector 
from tkinter import *


def submitact():
	
	user = Username.get()
	passw = password.get()

	print(f"The name entered by you is {user} {passw}")

	logintodb(user, passw)


def logintodb(user, passw):
	
	# If paswword is enetered by the 
	# user
	if passw:
		db = mysql.connector.connect(host ="localhost",
									user = user,
									password = passw,
									db ="College")
		cursor = db.cursor()
		
	# If no password is enetered by the
	# user
	else:
		db = mysql.connector.connect(host ="localhost",
									user = user,
									db ="College")
		cursor = db.cursor()
		
	# A Table in the database
	savequery = "select * from STUDENT"
	
	try:
		cursor.execute(savequery)
		myresult = cursor.fetchall()
		
		# Printing the result of the
		# query
		for x in myresult:
			print(x)
		print("Excecuted successfully")
		
	except:
		db.rollback()
		print("Error occured")


root = tk.Tk()
root.geometry("600x600")
root.title("LOGIN SYSTEM PYTHON-ANSWER")


# Definging the first row
lblfrstrow = tk.Label(root, text ="USER ID ->", )
lblfrstrow.place(x = 50, y = 20)

Username = tk.Entry(root, width = 35)
Username.place(x = 150, y = 20, width = 100)

lblsecrow = tk.Label(root, text ="Password ->")
lblsecrow.place(x = 50, y = 50)

password = tk.Entry(root, width = 35)
password.place(x = 150, y = 50, width = 100)

submitbtn = tk.Button(root, text ="Login", 
					bg ='blue', command = submitact)
submitbtn.place(x = 150, y = 135, width = 55)

root.mainloop()
Posted by: Guest on March-16-2021

Python Answers by Framework

Browse Popular Code Answers by Language