Answers for "how to do fizzbuzz in python"

2

fizz buzz python

def fizz_buzz(input):
    if (input % 3 == 0) and (input % 5 == 0):
        return "FizzBuzz"
    if input % 3 == 0:
        return "Fizz"
    if input % 5 == 0:
        return "Buzz"
    else:
        return input


print(fizz_buzz(3))
Posted by: Guest on June-22-2020
1

fizzbuzz python

def minInput():
    Min = 1
    return(Min)
def maxInput():
    Max=100
    return(Max)
  
def creator(i):
    item = ""
    
    if task(i,3,"fizz")=="fizz":
        item = item+task(i,3,"fizz")
    if task(i,5,"buzz")=="buzz":
        item = item+task(i,5,"buzz")
    if task(i,7,"pezz")=="pezz":
        item = item+task(i,7,"pezz")
        
    if item == "":
        item = i
    return item

def task(i,d,word):
    if i%d==0:
        return (word)

def main():
    Max = maxInput()
    Min = minInput()
    for i in range(Min,Max):
        print(creator(i))
main()
Posted by: Guest on November-02-2020
2

how to make fizzbuzz in python

for x in range(100):
  output = ""
  if x % 3 == 0:
    output += "Fizz"
  if x % 5 == 0:
    output += "Buzz"
  print(output)
Posted by: Guest on January-05-2020
0

python fizzbuzz solution

# check prime number
def prime(n):
    if n > 1:
        for i in range(2, n):
            if (n % i) == 0:
                break
        else:
            print(n, "prime number")


for num in range(1, 100):
    result = ""
    if prime(num):
        result += "Prime"
    else:
        if num % 3 == 0 and num % 5 == 0:
            result += "FizzBuzz"
            print(num, result)
        elif num % 3 == 0:
            result += "Fizz"
            print(num, result)
        elif num % 5 == 0:
            result += "Buzz"
            print(num, result)
        else:
            print(num)


if __name__ == '__main__':

    print('All done')
Posted by: Guest on August-22-2020
1

fizzbuzz in python

def fizzBuzz(size):
    for i in range(size - (size -1), size + 1):
        localResult = "fizz" if not i % 3 else ""
        localResult = localResult + "buzz" if not i % 5 else localResult
        localResult = str(i) if localResult == "" else localResult
        print(localResult)
Posted by: Guest on August-04-2020

Python Answers by Framework

Browse Popular Code Answers by Language