python loops
#x starts at 1 and goes up to 80 @ intervals of 2
for x in range(1, 80, 2):
print(x)python loops
#x starts at 1 and goes up to 80 @ intervals of 2
for x in range(1, 80, 2):
print(x)for loop python
Python Loops
for x in range(1, 80, 2):
print(x)
words=['zero','one','two']
for operator, word in enumerate(words):
print(word, operator)
for x in range(1, 80, 2):
print(x)python for loop
#to print number from 1 to 10
for i in range(1,11):
print(i)
#to print a list
l = [1,2,3,4]
for i in l:
print(i)
r = ["a","b","c","d","e"]
s = [1,2,3,4,5]
#print two list with the help of zip function
for p,q in zip(r,s):
print(p,q)python for loop
# Python for loop
for i in range(1, 101):
# i is automatically equals to 0 if has no mention before
# range(1, 101) is making the loop 100 times (range(1, 151) will make it to loop 150 times)
print(i) # prints the number of i (equals to the loop number)
for x in [1, 2, 3, 4, 5]:
# it will loop the length of the list (in that case 5 times)
print(x) # prints the item in the index of the list that the loop is currently onpython for loop
for i in range(5):
print(i)
# Output:
# 0
# 1
# 2
# 3
# 4
my_list = ["a", 1, True, 4.0, (0, 0)]
for i in my_list:
print(i)
# Output:
# a
# 1
# True
# 4.0
# (0, 0)python for loop
# Python for Loops
# There are 2 types of for loops, list and range.
# List:
food = ['chicken', 'banana', 'pie']
for meal in food: # Structure: for <temporary variable name> in <list name>:
print(meal)
# Will use the temporary variable 'meal' every time it finds an item in the list, and print it
# So output is: chickennbanananpien
# Range:
for number in range(9): # Will loop 9 times and temporaray variable number will start at 0 and end at 8
print(number) # Prints variable 'number'Copyright © 2021 Codeinu
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