python dictonary of dictonary
from collections import defaultdict
d = defaultdict(dict)
d['dict1']['innerkey'] = 'value'
>>> d # currently a defaultdict type
defaultdict(<type 'dict'>, {'dict1': {'innerkey': 'value'}})
>>> dict(d) # but is exactly like a normal dictionary.
{'dict1': {'innerkey': 'value'}}how to use dictionaries in python
student_data = {
"name":"inderpaal",
"age":21,
"course":['Bsc', 'Computer Science']
}
#the keys are the left hand side and the values are the right hand side
#to print data you do print(name_of_dictionary['key_name'])
print(student_data['name']) # will print 'inderpaal'
print(student_data['age']) # will print 21
print(student_data['course'])[0]
#this will print 'Bsc' since that field is an array and array[0] is 'Bsc'python list of dictionaries
new_player1 = { 'firstName': 'LaMarcus', 'lastName': 'Aldridge', 'jersey': '12', 'heightMeters': '2.11', 'nbaDebutYear': '2006', 'weightKilograms': '117.9'}
new_player2 = { 'firstName': 'LeBron', 'lastName': 'James', 'jersey': '2', 'heightMeters': '2.03', 'nbaDebutYear': '2003', 'weightKilograms': '113.4' }
new_player3 = { 'firstName': 'Kawhi', 'lastName': 'Leonard', 'jersey': '2', 'heightMeters': '2.01', 'nbaDebutYear': '2011', 'weightKilograms': '104.3' }
nba_players = []
nba_players.append(player)
nba_players.append(new_player1)
nba_players.append(new_player2)
nba_players.append(new_player3)Nested dictionary Python
IDs = ['emp1','emp2','emp3']
EmpInfo = [{'name': 'Bob', 'job': 'Mgr'},
{'name': 'Kim', 'job': 'Dev'},
{'name': 'Sam', 'job': 'Dev'}]
D = dict(zip(IDs, EmpInfo))
print(D)
# Prints {'emp1': {'name': 'Bob', 'job': 'Mgr'},
# 'emp2': {'name': 'Kim', 'job': 'Dev'},
# 'emp3': {'name': 'Sam', 'job': 'Dev'}}Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
