apply lambda with if
df['new column name'] = df['column name'].apply(lambda x: 'value if condition is met' if x condition else 'value if condition is not met')
apply lambda with if
df['new column name'] = df['column name'].apply(lambda x: 'value if condition is met' if x condition else 'value if condition is not met')
how to use if else in lambda python
lambda <arguments> : <Return Value if condition is True> if <condition> else <Return Value if condition is False>
lambda x : True if (x > 10 and x < 20) else False
lambda condition python
f = lambda parameter : exp1 if cond else exp2
# example
f = lambda x: "even" if x%2==0 else "odd"
python lambda function if else
# Think of the lambda function as defining a REALLY small function without
# a name.
# EXAMPLE #
lis = [2, 4, 6, 8]
output = lambda [parameter] : return True if [parameter] in lis else return False
print(output[4])
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