scanning 2d array in python
If you want to take n lines of input where each line contains m space separated integers like:
1 2 3
4 5 6
7 8 9
a=[] // declaration
for i in range(0,n): //where n is the no. of lines you want
a.append([int(j) for j in input().split()]) // for taking m space separated integers as inputhow to create 2d list in python
o=[]
for i in range(0,rows):
x=[]
for j in range(0,cols):
x.append(0)
o.append(x)
#if you use [[0]*cols]*rows all rows will become the same list
#so editing in one row will edit all rows2d array in python
from array import *
T = [[11, 12, 5, 2], [15, 6,10], [10, 8, 12, 5], [12,15,8,6]]
for r in T:
for c in r:
print(c,end = " ")
print()create a 2d array in python
def build_matrix(rows, cols):
matrix = []
for r in range(0, rows):
matrix.append([0 for c in range(0, cols)])
return matrix
if __name__ == '__main__':
build_matrix(6, 10)2d array python3
# 5x6, 2-d array of booleans using list comprehension:
matrix = [[False for col in range(6)] for row in range(5)]
# 6x5, 2-d array of banana's using list comprehension:
matrix = [['banana' for col in range(5)] for row in range(6)]2D array python
# 2D arrays in python can be used to create rudimentary games
array_2d = [['row0, column0'], ['row0, column1'], ['row0, column2'],
['row1, column0'], ['row1, column1'], ['row1, column2'],
['row2, column0'], ['row2, column1'], ['row2, column2']]Copyright © 2021 Codeinu
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