sort by index 2d array python
a = [[9, 9, 2], [9, 9, 3], [9, 9, 8], [9, 9, 4], [9, 9, 1], [9, 9, 5]]
b = sorted(a, key=lambda a:a[2])
#b contains the following arrays, sorted by their second index:
[[9, 9, 1], [9, 9, 2], [9, 9, 3], [9, 9, 4], [9, 9, 5], [9, 9, 8]]python get index of item in 2d list
myList = [[1, 2], [3, 4], [5, 6]]
def index_2d(myList, v):
for i, x in enumerate(myList):
if v in x:
return i, x.index(v)
print(index_2d(myList, 3))
# you get
# (1, 0)create a 2d array in python
def build_matrix(rows, cols):
matrix = []
for r in range(0, rows):
matrix.append([0 for c in range(0, cols)])
return matrix
if __name__ == '__main__':
build_matrix(6, 10)Copyright © 2021 Codeinu
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