regex find a word index of all matches
import re sentence = input("Give me a sentence ") word = input("What word would you like to find ") for match in re.finditer(word, sentence): print (match.start(), match.end())
regex find a word index of all matches
import re sentence = input("Give me a sentence ") word = input("What word would you like to find ") for match in re.finditer(word, sentence): print (match.start(), match.end())
regex match exact string
you want to achieve a case insensitive match for the word "rocket" surrounded by non-alphanumeric characters. A regex that would work would be: W*((?i)rocket(?-i))W*
re.match() python
import re pattern = '^a...s test_string = 'abyss' result = re.match(pattern, test_string) if result: print("Search successful.") else: print("Search unsuccessful.")
python .findall
## Search for pattern 'bb' in string 'aabbcc'. ## All of the pattern must match, but it may appear anywhere. ## On success, match.group() is matched text. match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb" match = re.search(r'cd', 'aabbcc') # not found, match == None ## . = any char but n match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc" ## d = digit char, w = word char match = re.search(r'ddd', 'p123g') # found, match.group() == "123" match = re.search(r'www', '@@abcd!!') # found, match.group() == "abc"
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