python replace regex
import re
s = "Example String"
replaced = re.sub('[ES]', 'a', s)
print replaced
# will print 'axample atring'python replace regex
import re
s = "Example String"
replaced = re.sub('[ES]', 'a', s)
print replaced
# will print 'axample atring'python regular expression
import re
# The string you want to find a pattern within
test_string = 'Hello greppers!'
# Creating a regular expression pattern
# This is a simple one which finds "Hello"
pattern = re.compile(r'Hello')
# This locates and returns all the occurences of the pattern
# within the test_string
match = pattern.finditer(test_string)
# Outputs all the ocurrences which were returned as
# as match objects
for match in matches:
print(match)re.match() python
import re
pattern = '^a...s$'
test_string = 'abyss'
result = re.match(pattern, test_string)
if result:
print("Search successful.")
else:
print("Search unsuccessful.")re python3
import re
>>> m = re.search('(?<=abc)def', 'abcdef')
>>> m.group(0)
'def'python .findall
## Search for pattern 'bb' in string 'aabbcc'.
## All of the pattern must match, but it may appear anywhere.
## On success, match.group() is matched text.
match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
match = re.search(r'cd', 'aabbcc') # not found, match == None
## . = any char but n
match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"
## d = digit char, w = word char
match = re.search(r'ddd', 'p123g') # found, match.group() == "123"
match = re.search(r'www', '@@abcd!!') # found, match.group() == "abc"python re
if pattern := re.search("[iI] am (.*)", "I am tired"):
print(f"Hi {pattern.group(1)}, I'm dad!")Copyright © 2021 Codeinu
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