python replace regex
import re
s = "Example String"
replaced = re.sub('[ES]', 'a', s)
print replaced
# will print 'axample atring'python replace regex
import re
s = "Example String"
replaced = re.sub('[ES]', 'a', s)
print replaced
# will print 'axample atring'python regex
import re
# Regex Cheat sheet : https://www.dataquest.io/blog/regex-cheatsheet/
# Regex python tester : https://pythex.org/
# re doc : https://docs.python.org/3/library/re.html
text = "i like train"
reg = r"[a-c]" #the group of char a to c
if re.match(reg, text): #Check if regex is correct
print(text)
else:
print("Not any match")python regex tester
Find below are online regex tester
https://regex101.com/
https://pythex.org/
http://www.pyregex.com/
https://www.debuggex.com/
Here you insert your regular expression and get the test result.
Thank you !!!python re compile
import re
# Compile a regular expression pattern into a regular expression object, which can be used for matching using its match(), search() and other methods, described below.
prog = re.compile(pattern)
result = prog.match(string)
# is equivalent to
result = re.match(pattern, string)python named group regex example
>>> re.search(r'(?P<name>[^-]+)-(?P<ver>d.d.d-d+).tar.gz', 'package_name-1.2.3-2004.tar.gz').groupdict()
{'name': 'package_name', 'ver': '1.2.3-2004'}python regular expression
import re
# The string you want to find a pattern within
test_string = 'Hello greppers!'
# Creating a regular expression pattern
# This is a simple one which finds "Hello"
pattern = re.compile(r'Hello')
# This locates and returns all the occurences of the pattern
# within the test_string
match = pattern.finditer(test_string)
# Outputs all the ocurrences which were returned as
# as match objects
for match in matches:
print(match)Copyright © 2021 Codeinu
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