python regex
import re
# Regex Cheat sheet : https://www.dataquest.io/blog/regex-cheatsheet/
# Regex python tester : https://pythex.org/
# re doc : https://docs.python.org/3/library/re.html
text = "i like train"
reg = r"[a-c]" #the group of char a to c
if re.match(reg, text): #Check if regex is correct
print(text)
else:
print("Not any match")python regular expression
import re
# The string you want to find a pattern within
test_string = 'Hello greppers!'
# Creating a regular expression pattern
# This is a simple one which finds "Hello"
pattern = re.compile(r'Hello')
# This locates and returns all the occurences of the pattern
# within the test_string
match = pattern.finditer(test_string)
# Outputs all the ocurrences which were returned as
# as match objects
for match in matches:
print(match)re python3
import re
>>> m = re.search('(?<=abc)def', 'abcdef')
>>> m.group(0)
'def'python .findall
## Search for pattern 'bb' in string 'aabbcc'.
## All of the pattern must match, but it may appear anywhere.
## On success, match.group() is matched text.
match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
match = re.search(r'cd', 'aabbcc') # not found, match == None
## . = any char but n
match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"
## d = digit char, w = word char
match = re.search(r'ddd', 'p123g') # found, match.group() == "123"
match = re.search(r'www', '@@abcd!!') # found, match.group() == "abc"python re
if pattern := re.search("[iI] am (.*)", "I am tired"):
print(f"Hi {pattern.group(1)}, I'm dad!")Copyright © 2021 Codeinu
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