Answers for "merge sort ascending order"

2

merge sort

// @see https://www.youtube.com/watch?v=es2T6KY45cA&vl=en
// @see https://www.cs.usfca.edu/~galles/visualization/ComparisonSort.html

function merge(list, start, midpoint, end) {
    const left = list.slice(start, midpoint);
    const right = list.slice(midpoint, end);
    for (let topLeft = 0, topRight = 0, i = start; i < end; i += 1) {
        if (topLeft >= left.length) {
            list[i] = right[topRight++];
        } else if (topRight >= right.length) {
            list[i] = left[topLeft++];
        } else if (left[topLeft] < right[topRight]) {
            list[i] = left[topLeft++];
        } else {
            list[i] = right[topRight++];
        }
    }
}

function mergesort(list, start = 0, end = undefined) {
    if (end === undefined) {
        end = list.length;
    }
    if (end - start > 1) {
        const midpoint = ((end + start) / 2) >> 0;
        mergesort(list, start, midpoint);
        mergesort(list, midpoint, end);
        merge(list, start, midpoint, end);
    }
    return list;
}

mergesort([4, 7, 2, 6, 4, 1, 8, 3]);
Posted by: Guest on May-31-2020
0

merge sort

# Python3 recursive merge sort algorithm -> O(n*log(n))
def merge_sort(A):
    def merge(l, r):
        i = j = 0
        n = []  # merging container
        while i < len(l) or j < len(r):

            # if no more elements to the right,
            # add remaining left elements
            if i == len(l):
                n.extend(r[j:])
                break

            # if no more elements to the left,
            # add remaining right elements
            if j == len(r):
                n.extend(l[i:])
                break

            # if elements left on both sides,
            # add smaller element
            a, b = l[i], r[j]
            if a < b:
                n.append(a)
                i += 1
            else:
                n.append(b)
                j += 1

        return n

    # divide list down to single-elements
    s = len(A)
    if s > 1:
        s //= 2
        l = merge_sort(A[:s])  # split left
        r = merge_sort(A[s:])  # split right
        return merge(l, r)  # merge sides in order
    else:
        return A
Posted by: Guest on January-16-2021

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