sort dictionary python
l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}python sort dictionary by key
def sort_dict(dictionary, rev = True):
l = list(dictionary.items())
l.sort(reverse = rev)
a = [item[1] for item in l]
z = ''
for x in a:
z = z + str(x)
return(z)Copyright © 2021 Codeinu
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