Answers for "how to sort a dictionary by key and value in one go"

1

how to sort dict by value

dict1 = {1: 1, 2: 9, 3: 4}
sorted_dict = {}
sorted_keys = sorted(dict1, key=dict1.get)  # [1, 3, 2]

for w in sorted_keys:
    sorted_dict[w] = dict1[w]

print(sorted_dict) # {1: 1, 3: 4, 2: 9}
Posted by: Guest on August-08-2021
0

sort a dictionary by value then key

d = {'apple': 2, 'banana': 3, 'almond':2 , 'beetroot': 3, 'peach': 4}
[v[0] for v in sorted(d.items(), key=lambda kv: (-kv[1], kv[0]))]
Posted by: Guest on March-06-2021

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