python sort a list using defined order
>>> sorted(A, key = lambda i: B.index(i[0]))
[[6, 1], [1, 3], [3, 5]]python sort a list using defined order
>>> sorted(A, key = lambda i: B.index(i[0]))
[[6, 1], [1, 3], [3, 5]]Copyright © 2021 Codeinu
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