sorted python lambda
lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)sorted python lambda
lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)sorted vs sort python
# The sort() function will modify the list it is called on.
# The sorted() function will create a new list
# containing a sorted version of the list it is given.
list = [4,8,2,1]
list.sort()
#--> list = [1,2,4,8] now
list = [4,8,2,1]
new_list = list.sorted()
#--> list = [4,8,2,1], but new_list = [1,2,4,8]sorted list python
sorted(iterable, key=None, reverse=False)
type(sorted(iterable, key=None, reverse=False)) = listpythonn sort example
gList = [ "Rocket League", "Valorant", "Grand Theft Autu 5"]
gList.sort()
# OUTPUT --> ['Grand Theft Auto 5', 'Rocket League', 'Valorant']
# It sorts the list according to their namespython lambda key sort
>>> student_tuples = [
... ('john', 'A', 15),
... ('jane', 'B', 12),
... ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2]) # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]Copyright © 2021 Codeinu
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