how to address a column in a 2d array python
>>> import numpy as np
>>> A = np.array([[1,2,3,4],[5,6,7,8]])
>>> A
array([[1, 2, 3, 4],
[5, 6, 7, 8]])
>>> A[:,2] # returns the third columm
array([3, 7])
how to address a column in a 2d array python
>>> import numpy as np
>>> A = np.array([[1,2,3,4],[5,6,7,8]])
>>> A
array([[1, 2, 3, 4],
[5, 6, 7, 8]])
>>> A[:,2] # returns the third columm
array([3, 7])
how get 1st column in all rows of a 2d matrix in python
data = [
['a', 1, 2],
['b', 3, 4],
['c', 5, 6]
]
columns = list(zip(*data))
print("column[0] = {}".format(columns[0]))
print("column[1] = {}".format(columns[1]))
print("column[2] = {}".format(columns[2]))
# output
>>> print("column[0] = {}".format(columns[0]))
column[0] = ('a', 'b', 'c')
>>> print("column[1] = {}".format(columns[1]))
column[1] = (1, 3, 5)
>>> print("column[2] = {}".format(columns[2]))
column[2] = (2, 4, 6)
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