python count number of unique elements in a list
# Basic syntax:
len(set(my_list))
# By definition, sets only contain unique elements, so when the list
# is converted to a set all duplicates are removed.
# Example usage:
my_list = ['so', 'so', 'so', 'many', 'duplicated', 'words']
len(set(my_list))
--> 4
# Note, list(set(my_list)) is a useful way to return a list containing
# only the unique elements in my_listcounting unique values python
df.loc[df['mID']=='A','hID'].agg(['nunique','count','size'])count unique values in python
words = ['a', 'b', 'c', 'a']
unique_words = set(words) # == set(['a', 'b', 'c'])
unique_word_count = len(unique_words) # == 3count unique values in python
aa="XXYYYSBAA"
bb=dict(zip(list(aa),[list(aa).count(i) for i in list(aa)]))
print(bb)
# output:
# {'X': 2, 'Y': 3, 'S': 1, 'B': 1, 'A': 2}Copyright © 2021 Codeinu
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