python remove duplicates from list
mylist = ["a", "b", "b", "c", "a"]
mylist = sorted(set(mylist))
print(mylist)python remove duplicates from list
mylist = ["a", "b", "b", "c", "a"]
mylist = sorted(set(mylist))
print(mylist)remove duplicates from sorted array
// Java
public int removeDuplicates(int[] nums) {
if (nums.length == 0) return 0;
int i = 0;
for (int j = 1; j < nums.length; j++) {
if (nums[j] != nums[i]) {
i++;
nums[i] = nums[j];
}
}
return i + 1;
}remove duplicates in sorted array python
# function for removing duplicates
def removeDuplicate(arr, n):
j = 0
# traverse elements of arr
for i in range(0, n-1):
# if ith element is not equal to (i+1)th element, then store ith value in arr[j]
if (arr[i] != arr[i+1]):
arr[j] = arr[i]
j = j+1
# store last value of arr in arr[j]
arr[j] = arr[n-1]
j = j+1
# print first j elements of array arr
for i in range(0, j):
print("%d"%(arr[i]), end = " ")
arr = [1, 3, 5, 5, 7, 9]
n = len(arr)
# calling function when number of elements in array is greater than 1
if (n > 1):
removeDuplicate(arr, n)remove duplicates from sorted array
def remove_duplicate(nums: [int]) -> int:
nums[:] = sorted(set(nums))
return len(nums)remove duplicates from sorted array
def remove_duplicates(nums: [int]) -> int:
cnt = 1
for index in range(len(nums) - 1):
if nums[index] != nums[index + 1]:
nums[cnt] = nums[index + 1]
cnt += 1
print(cnt)remove duplicates in sorted array python
j = 0
// traverse elements of arr
for i=0 to n-2
// if ith element is not equal to (i+1)th element of arr, then store ith value in arr[j]
if arr[i] != arr[i+1]
arr[j] = arr[i]
j += 1
// store last value of arr in temp
arr[j] = arr[n-1]
j += 1
// print first j elements of array arr
for i=0 to j-1
print arr[i]Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
