print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)python check for exception
try: # put here the code that you expect to error
# code
except ValueError: # if you want to catch a ValueError
# NOTE: you CANNOT catch a syntax error
# (UNLESS you are trying to execute code from a string with eval())
# code if python caught the exception
except NameError: # you can catch multiple types of errors!
# TIP: you can leave the error type blank to make python catch all types of errors!
# code if another exception is caught (this is pretty much a modified if statement)
else: # if no error has been caught do the following:
# code if no exception has been caughtCopyright © 2021 Codeinu
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