print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)python defualt error handler
import sys
def my_except_hook(exctype, value, traceback):
if exctype == KeyboardInterrupt:
print "Handler code goes here"
else:
sys.__excepthook__(exctype, value, traceback)
sys.excepthook = my_except_hookCopyright © 2021 Codeinu
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