print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)python continue
nums = [7,3,-1,8,-9]
positive_nums = []
for num in nums:
if num < 0: #skips to the next iteration
continue
positive_nums.append(num)
print(positive_nums) # 7,3,8python try except continue loop
try:
#code
except:
#pass to continue loop or error handling
pass
else:
#code
pass
finally:
passCopyright © 2021 Codeinu
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