reverse intergers in python
# Get the number from user manually
num = int(input("Enter your favourite number: "))
# Initiate value to null
test_num = 0
# Check using while loop
while(num>0):
#Logic
remainder = num % 10
test_num = (test_num * 10) + remainder
num = num//10
# Display the result
print("The reverse number is : {}".format(test_num))python reverse
my_list = [1, 2, 3]
my_list.reverse() # my_list is modified
print(my_list) # '[3, 2, 1]'
my_revert = my_list[::-1] # my_list stays [3, 2, 1]
print(my_revert) # '[1, 2, 3]'
# Item by item reverse with range(<start>, <end>, <step>)
for i in range(len(my_list), 0, -1): # my_list is [3, 2, 1]
print(my_list[i-1]) # '1' '2' '3'
for i in reversed(range(len(my_list))):
print(my_list[i]) # '1' '2' '3'Copyright © 2021 Codeinu
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