python range reverse
When you call range() with three arguments, you can choose not only
where the series of numbers will start and stop but also how big the
difference will be between one number and the next.
range(start, stop, step)
If your 'step' is negative and 'start' is bigger than 'stop', then
you move through a series of decreasing numbers.
for i in range(10,0,-1):
print(i, end=' ')
# Output: 10 9 8 7 6 5 4 3 2 1python reverse range
my_list = [1, 2, 3]
my_list.reverse() # my_list is modified
print(my_list) # '[3, 2, 1]'
my_revert = my_list[::-1] # my_list stays [3, 2, 1]
print(my_revert) # '[1, 2, 3]'
# Item by item reverse with range(<start>, <end>, <step>)
for i in range(len(my_list), 0, -1): # my_list is [3, 2, 1]
print(my_list[i-1]) # '1' '2' '3'
for i in reversed(range(len(my_list))):
print(my_list[i]) # '1' '2' '3'reversed(range
>>> type(range(3))
<class 'range'>Copyright © 2021 Codeinu
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