inverted for python
for i in reversed(range(5)):
print(i)inverted for python
for i in reversed(range(5)):
print(i)python range reverse
When you call range() with three arguments, you can choose not only
where the series of numbers will start and stop but also how big the
difference will be between one number and the next.
range(start, stop, step)
If your 'step' is negative and 'start' is bigger than 'stop', then
you move through a series of decreasing numbers.
for i in range(10,0,-1):
print(i, end=' ')
# Output: 10 9 8 7 6 5 4 3 2 1reverse intergers in python
# Get the number from user manually
num = int(input("Enter your favourite number: "))
# Initiate value to null
test_num = 0
# Check using while loop
while(num>0):
#Logic
remainder = num % 10
test_num = (test_num * 10) + remainder
num = num//10
# Display the result
print("The reverse number is : {}".format(test_num))python reverse
my_list = [1, 2, 3]
my_list.reverse() # my_list is modified
print(my_list) # '[3, 2, 1]'
my_revert = my_list[::-1] # my_list stays [3, 2, 1]
print(my_revert) # '[1, 2, 3]'
# Item by item reverse with range(<start>, <end>, <step>)
for i in range(len(my_list), 0, -1): # my_list is [3, 2, 1]
print(my_list[i-1]) # '1' '2' '3'
for i in reversed(range(len(my_list))):
print(my_list[i]) # '1' '2' '3'reverse function python
# The Reverse operation - Python 3:
Some_List = [1, 2, 3, 4, 1, 2, 6]
Some_List.reverse()
print(Some_List)
# Result: [6, 2, 1, 4, 3, 2, 1]reverse python3
arr = [2,5,32,86,4,131,97]
# reverse without modifying input, using range:
for i in range(len(arr)-1, -1, -1):
print(arr[i])
# reverse and modifying input:
arr.reverse()Copyright © 2021 Codeinu
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