Answers for "range count backwards python"

python range reverse

When you call range() with three arguments, you can choose not only 
where the series of numbers will start and stop but also how big the 
difference will be between one number and the next.

range(start, stop, step)

If your 'step' is negative and 'start' is bigger than 'stop', then 
you move through a series of decreasing numbers.

for i in range(10,0,-1):
    print(i, end=' ')
# Output: 10 9 8 7 6 5 4 3 2 1

how to count backwards in for loop python

# for i in range(start, end, step)
for i in range(5, 0, -1):
    print(i)
5
4
3
2
1

python reverse range

my_list = [1, 2, 3]
my_list.reverse()           # my_list is modified
print(my_list)              # '[3, 2, 1]'
my_revert = my_list[::-1]   # my_list stays [3, 2, 1]
print(my_revert)            # '[1, 2, 3]'
# Item by item reverse with range(<start>, <end>, <step>)
for i in range(len(my_list), 0, -1):		# my_list is [3, 2, 1]
    print(my_list[i-1])		# '1' '2' '3'
for i in reversed(range(len(my_list))):
    print(my_list[i])       # '1' '2' '3'