Answers for "applying lambda function to dataframe column"

3

pandas apply function to each row lambda

def EOQ(D,p,ck,ch):
    Q = math.sqrt((2*D*ck)/(ch*p))
    return Q
ch=0.2
ck=5
df['Q'] = df.apply(lambda row: EOQ(row['D'], row['p'], ck, ch), axis=1)
df
Posted by: Guest on August-23-2020
-2

use apply with lambda pandas

df.apply(lambda x: func(x['col1'],x['col2']),axis=1)
Posted by: Guest on November-14-2020

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