pandas apply function to column
df['a'] = df['a'].apply(lambda x: x + 1)pandas apply function to column
df['a'] = df['a'].apply(lambda x: x + 1)pandas for column in dataframe
for column in df:
print(df[column])pandas apply function to each row lambda
def EOQ(D,p,ck,ch):
Q = math.sqrt((2*D*ck)/(ch*p))
return Q
ch=0.2
ck=5
df['Q'] = df.apply(lambda row: EOQ(row['D'], row['p'], ck, ch), axis=1)
dfCopyright © 2021 Codeinu
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