pandas apply function to each row lambda
def EOQ(D,p,ck,ch):
Q = math.sqrt((2*D*ck)/(ch*p))
return Q
ch=0.2
ck=5
df['Q'] = df.apply(lambda row: EOQ(row['D'], row['p'], ck, ch), axis=1)
dfpandas apply function to each row lambda
def EOQ(D,p,ck,ch):
Q = math.sqrt((2*D*ck)/(ch*p))
return Q
ch=0.2
ck=5
df['Q'] = df.apply(lambda row: EOQ(row['D'], row['p'], ck, ch), axis=1)
dfpandas apply function to dataframe
# iterate using this syntax where df is the pandas.DataFrame
# N. B.: a single tuple is composed by the row index
# and the values of the dataframe columns
for row in df.itertuples():
# do your stuff hereCopyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
