python bytes to int
""" Python 3 """ # int.from_bytes( bytes, byteorder, *, signed=False ) # bytes must evaluate as bytes-like object # byteorder is optional. someString must evaluate as 'big' xor 'little' # signed is optional. someBoolean opmust evaluate as boolean # examples: someBytes = b'x00x01x00x02x00x03' someInteger = int.from_bytes(someBytes) someInteger = int.from_bytes(someBytes, 'big') someInteger = int.from_bytes(someBytes, byteorder='little', signed=True) """ Python 2.7 """ # no bytes is str in Python 2.7 import struct struct.unpack(pattern, someBytes) # someBytes is of type str or byte array # pattern is a string begining with '>' or '<', # followed by as many 'H' or 'B' chars needed # to cover the someBytes' length. # '>' stands for Big-endian # '<' stands for Big-endian # 'H' stands for 2 bytes unsigned short integer # 'B' stands for 1 byte unsigned char # examples: >>> import struct >>> sixBytes = b'x00x01x00x02x00x03' >>> struct.unpack('>HHH', sixBytes) (1, 2, 3) >>> struct.unpack('<HHH', sixBytes) (256, 512, 768) >>> struct.unpack('>BBBBBB', sixBytes) (0, 1, 0, 2, 0, 3) >>> struct.unpack('<BBBBBB', sixBytes) (0, 1, 0, 2, 0, 3)
