Answers for "threading without semaphore python"

4

threading python

import threading
import time

def thread_function(name):
     print(f"Thread {name}: starting")
     time.sleep(2)
     print(f"Thread {name}: finishing")
 
my_thread = threading.Thread(target=thread_function, args=(1,))
my_thread.start()
time.sleep(1)
my_second_thread = threading.Thread(target=thread_function, args=(2,))
my_second_thread.start()
my_second_thread.join() # Wait until thread finishes to exit
Posted by: Guest on October-15-2020
0

python daemon thread

import threading
import time
 
shared_resource = False # Set the resource to False initially
lock = threading.Lock() # A lock for the shared resource
 
def perform_computation():
    # Thread A will call this function and manipulate the resource
    print(f'Thread {threading.currentThread().name} - performing some computation....')
    shared_resource = True
    print(f'Thread {threading.currentThread().name} - set shared_resource to True!')
    print(f'Thread {threading.currentThread().name} - Finished!')
    time.sleep(1)
 
def monitor_resource():
    # Thread B will monitor the shared resource
    while shared_resource == False:
        time.sleep(1)
    print(f'Daemon Thread {threading.currentThread().name} - Detected shared_resource = False')
    time.sleep(1)
    print(f'Daemon Thread {threading.currentThread().name} - Finished!')
 
 
if __name__ == '__main__':
    a = threading.Thread(target=perform_computation, name='A')
    b = threading.Thread(target=monitor_resource, name='B', daemon=True) # Make thread B as a daemon thread
 
    # Now start both threads
    a.start()
    b.start()
Posted by: Guest on January-22-2021

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