removing items in a list python
fruits = ["apple", "banana", "cherry"]
fruits.remove(fruits[0])
print(fruits)removing items in a list python
fruits = ["apple", "banana", "cherry"]
fruits.remove(fruits[0])
print(fruits)python remove element from list
myList = ["hello", 8, "messy list", 3.14] #Creates a list
myList.remove(3.14) #Removes first instance of 3.14 from myList
print(myList) #Prints myList
myList.remove(myList[1]) #Removes first instance of the 2. item in myList
print(myList) #Prints myList
#Output will be the following (minus the hastags):
#["hello", 8, "messy list"]
#["hello", "messy list"]Python Remove List Items
thislist = ["apple", "banana", "cherry"]
thislist.remove("banana")
print(thislist)remove list from list python
>>> a = range(1, 10)
>>> [x for x in a if x not in [2, 3, 7]]
[1, 4, 5, 6, 8, 9]delete something from list python
import random
#Let's say that we have a list of names.
listnames = ['Miguel', 'James', 'Kolten']
#Now, I choose a random one to remove.
removing = random.choice(listnames)
#And to delete, I do this:
listnames.remove(remove)remove one value from list more than once
# list with integer elements
list = [10, 20, 10, 30, 10, 40, 10, 50]
# number (n) to be removed
n = 10
# print original list
print ("Original list:")
print (list)
# loop to traverse each element in list
# and, remove elements
# which are equals to n
i=0 #loop counter
length = len(list) #list length
while(i<length):
if(list[i]==n):
list.remove (list[i])
# as an element is removed
# so decrease the length by 1
length = length -1
# run loop again to check element
# at same index, when item removed
# next item will shift to the left
continue
i = i+1
# print list after removing given element
print ("list after removing elements:")
print (list)Copyright © 2021 Codeinu
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