Answers for "pop a value from list python"

python remove value from list

# Below are examples of 'remove', 'del', and 'pop' 
#   methods of removing from a python list
""" 'remove' removes the first matching value, not a specific index: """
>>> a = [0, 2, 3, 2]
>>> a.remove(2)
>>> a
[0, 3, 2]

""" 'del' removes the item at a specific index: """
>>> a = [9, 8, 7, 6]
>>> del a[1]
>>> a
[9, 7, 6]

""" 'pop' removes the item at a specific index and returns it. """
>>> a = [4, 3, 5]
>>> a.pop(1)
3
>>> a
[4, 5]

""" Their error modes are different too: """
>>> a = [4, 5, 6]
>>> a.remove(7)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: list.remove(x): x not in list
>>> del a[7]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
IndexError: list assignment index out of range
>>> a.pop(7)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
IndexError: pop index out of range

python pop element

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop()
-->[123, 'Add', 'Grepper'] #last element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop(0)
-->['Add', 'Grepper', 'Answer'] #first element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
any_index_of_the_list = 2
my_list.pop(any_index_of_the_list)
-->[123, 'Add', 'Answer'] #element at index 2 is removed 
						  #(first element is 0)

how to pop things out of list python

>>> l = ['a', 'b', 'c', 'd']
>>> l.pop(0)
'a'
>>> l
['b', 'c', 'd']